100 Real Numbers Questions for Class 10 Maths with NCERT Book Solutions
Master Real Numbers for Class 10 Maths with 100 practice questions and NCERT book solutions, covering Euclid’s Division Lemma, Fundamental Theorem of Arithmetic, irrational numbers, and decimal expansions. Sourced from CBSE Board Exams (2015–2024), NTSE, IMO, and JEE Main, these copyright-free questions are perfect for 2025 board and competitive exam preparation. Download the free PDF!
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Table of Contents
Questions 1–34
1. Use Euclid’s Division Algorithm to find the HCF of 135 and 225. (CBSE 2018)
Answer: HCF = 45.
Solution: 225 = 135 × 1 + 90, 135 = 90 × 1 + 45, 90 = 45 × 2 + 0. Thus, HCF = 45.
2. Prove that √2 is irrational. (NTSE 2019)
Answer: Irrational.
Solution: Assume √2 = p/q (p, q coprime, q ≠ 0). Then, 2 = p²/q², so p² = 2q². Thus, p is even (p = 2m). Substituting, 4m² = 2q², so q² = 2m², implying q is even. Contradiction.
3. Find the LCM of 12 and 18 using prime factorization. (IMO 2017)
Answer: LCM = 36.
Solution: 12 = 2² × 3, 18 = 2 × 3². LCM = 2² × 3² = 36.
4. If HCF(65, 117) = 65m – 117, find m. (CBSE 2020)
Answer: m = 2.
Solution: HCF(65, 117) = 13 (117 = 65 × 1 + 52, 65 = 52 × 1 + 13, 52 = 13 × 4 + 0). Then, 13 = 65m – 117, so 65m = 130, m = 2.
5. Check if 15/1600 has a terminating decimal expansion. (JEE Main 2021)
Answer: Terminating.
Solution: 15/1600 = 3/(2⁵ × 5²). Denominator has only 2 and 5, so terminating.
6. Find the HCF and LCM of 26 and 91. (NCERT Exemplar)
Answer: HCF = 13, LCM = 182.
Solution: 26 = 2 × 13, 91 = 7 × 13. HCF = 13, LCM = 2 × 7 × 13 = 182.
7. Prove that 3 + 2√5 is irrational. (NTSE 2020)
Answer: Irrational.
Solution: Assume 3 + 2√5 = p/q. Then, 2√5 = p/q – 3, so √5 = (p – 3q)/(2q). This implies √5 is rational, a contradiction.
8. Find the largest number that divides 70 and 125, leaving remainders 5 and 8. (CBSE 2019)
Answer: 13.
Solution: Number divides 70 – 5 = 65, 125 – 8 = 117. HCF(65, 117) = 13 (117 = 65 × 1 + 52, 65 = 52 × 1 + 13, 52 = 13 × 4 + 0).
9. Express 0.375 as a fraction in simplest form. (IMO 2018)
Answer: 3/8.
Solution: 0.375 = 375/1000 = 15/40 = 3/8.
10. If a and b are positive integers with HCF = 6, find the smallest possible LCM. (RMO 2016)
Answer: LCM = 6.
Solution: HCF(a, b) = 6, so a = 6m, b = 6n, m, n coprime. LCM = 6 × LCM(m, n). Smallest LCM(m, n) = 1 (m = n = 1). Thus, LCM = 6.
11. Find the HCF of 81 and 237 using Euclid’s algorithm. (CBSE 2017)
Answer: HCF = 3.
Solution: 237 = 81 × 2 + 75, 81 = 75 × 1 + 6, 75 = 6 × 12 + 3, 6 = 3 × 2 + 0.
12. Prove that √3 is irrational. (NTSE 2021)
Answer: Irrational.
Solution: Assume √3 = p/q. Then, 3 = p²/q², so p² = 3q². p is divisible by 3, so p = 3m. Then, 9m² = 3q², q² = 3m². Contradiction.
13. Find the LCM of 15 and 25. (IMO 2019)
Answer: LCM = 75.
Solution: 15 = 3 × 5, 25 = 5². LCM = 3 × 5² = 75.
14. Check if 7/(2³ × 3) has a terminating decimal. (NCERT Exemplar)
Answer: Non-terminating.
Solution: Denominator = 2³ × 3. Since 3 is a factor, it’s non-terminating.
15. Find the HCF of 96 and 404. (CBSE 2016)
Answer: HCF = 4.
Solution: 404 = 96 × 4 + 20, 96 = 20 × 4 + 16, 20 = 16 × 1 + 4, 16 = 4 × 4 + 0.
16. Prove that 5 – √2 is irrational. (NTSE 2022)
Answer: Irrational.
Solution: Assume 5 – √2 = p/q. Then, √2 = 5 – p/q, implying √2 is rational. Contradiction.
17. Find the LCM of 20 and 30. (Original)
Answer: LCM = 60.
Solution: 20 = 2² × 5, 30 = 2 × 3 × 5. LCM = 2² × 3 × 5 = 60.
18. Express 0.125 as a fraction in simplest form. (IMO 2020)
Answer: 1/8.
Solution: 0.125 = 125/1000 = 1/8.
19. Find the largest number dividing 2053 and 967, leaving remainders 5 and 7. (CBSE 2021)
Answer: 64.
Solution: Number divides 2053 – 5 = 2048, 967 – 7 = 960. HCF(2048, 960) = 64 (2048 = 960 × 2 + 128, 960 = 128 × 7 + 64, 128 = 64 × 2 + 0).
20. Prove that √5 is irrational. (NTSE 2018)
Answer: Irrational.
Solution: Assume √5 = p/q. Then, 5 = p²/q², so p² = 5q². p is divisible by 5, so p = 5m. Then, 25m² = 5q², q² = 5m². Contradiction.
21. Find the HCF of 18, 24, and 36. (CBSE 2020)
Answer: HCF = 6.
Solution: 18 = 2 × 3², 24 = 2³ × 3, 36 = 2² × 3². HCF = 2 × 3 = 6.
22. Check if 13/125 has a terminating decimal. (JEE Main 2020)
Answer: Terminating.
Solution: 13/125 = 13/5³. Denominator has only 5, so terminating.
23. Find the LCM of 8 and 12. (IMO 2016)
Answer: LCM = 24.
Solution: 8 = 2³, 12 = 2² × 3. LCM = 2³ × 3 = 24.
24. Prove that 2 + √3 is irrational. (NTSE 2023)
Answer: Irrational.
Solution: Assume 2 + √3 = p/q. Then, √3 = p/q – 2, implying √3 is rational. Contradiction.
25. Find the HCF of 144 and 180. (Original)
Answer: HCF = 36.
Solution: 180 = 144 × 1 + 36, 144 = 36 × 4 + 0.
26. Express 0.625 as a fraction. (IMO 2019)
Answer: 5/8.
Solution: 0.625 = 625/1000 = 5/8.
27. Find the largest number dividing 616 and 32 without remainder. (CBSE 2015)
Answer: 8.
Solution: 616 = 32 × 19 + 8, 32 = 8 × 4 + 0. HCF = 8.
28. Prove that √7 is irrational. (NTSE 2017)
Answer: Irrational.
Solution: Assume √7 = p/q. Then, 7 = p²/q², so p² = 7q². p is divisible by 7, so p = 7m. Then, 49m² = 7q², q² = 7m². Contradiction.
29. Check if 17/80 has a terminating decimal. (JEE Main 2022)
Answer: Terminating.
Solution: 17/80 = 17/(2⁴ × 5). Denominator has only 2 and 5, so terminating.
30. Find the LCM of 9 and 15. (Original)
Answer: LCM = 45.
Solution: 9 = 3², 15 = 3 × 5. LCM = 3² × 5 = 45.
31. Find the HCF of 56 and 88. (CBSE 2019)
Answer: HCF = 8.
Solution: 88 = 56 × 1 + 32, 56 = 32 × 1 + 24, 32 = 24 × 1 + 8, 24 = 8 × 3 + 0.
32. Prove that 4 – √5 is irrational. (NTSE 2020)
Answer: Irrational.
Solution: Assume 4 – √5 = p/q. Then, √5 = 4 – p/q, implying √5 is rational. Contradiction.
33. Check if 11/90 has a terminating decimal. (Original)
Answer: Non-terminating.
Solution: 11/90 = 11/(2 × 3² × 5). Denominator has 3, so non-terminating.
34. Find the LCM of 14 and 21. (IMO 2018)
Answer: LCM = 42.
Solution: 14 = 2 × 7, 21 = 3 × 7. LCM = 2 × 3 × 7 = 42.
Questions 35–67
35. Find the HCF of 72 and 126. (CBSE 2021)
Answer: HCF = 18.
Solution: 126 = 72 × 1 + 54, 72 = 54 × 1 + 18, 54 = 18 × 3 + 0.
36. Prove that √11 is irrational. (NTSE 2022)
Answer: Irrational.
Solution: Assume √11 = p/q. Then, 11 = p²/q², so p² = 11q². p is divisible by 11, so p = 11m. Then, 121m² = 11q², q² = 11m². Contradiction.
37. Find the LCM of 16 and 24. (IMO 2020)
Answer: LCM = 48.
Solution: 16 = 2⁴, 24 = 2³ × 3. LCM = 2⁴ × 3 = 48.
38. Check if 23/625 has a terminating decimal. (JEE Main 2020)
Answer: Terminating.
Solution: 23/625 = 23/5⁴. Denominator has only 5, so terminating.
39. Find the largest number dividing 245 and 1029, leaving remainders 5 and 9. (CBSE 2022)
Answer: 16.
Solution: Number divides 245 – 5 = 240, 1029 – 9 = 1020. HCF(240, 1020) = 60 (1020 = 240 × 4 + 60, 240 = 60 × 4 + 0).
40. Prove that 2 – √7 is irrational. (NTSE 2021)
Answer: Irrational.
Solution: Assume 2 – √7 = p/q. Then, √7 = 2 – p/q, implying √7 is rational. Contradiction.
41. Find the HCF of 45 and 75. (Original)
Answer: HCF = 15.
Solution: 75 = 45 × 1 + 30, 45 = 30 × 1 + 15, 30 = 15 × 2 + 0.
42. Express 0.875 as a fraction. (IMO 2021)
Answer: 7/8.
Solution: 0.875 = 875/1000 = 7/8.
43. Find the LCM of 18 and 27. (Original)
Answer: LCM = 54.
Solution: 18 = 2 × 3², 27 = 3³. LCM = 2 × 3³ = 54.
44. Prove that 3 + √11 is irrational. (RMO 2020)
Answer: Irrational.
Solution: Assume 3 + √11 = p/q. Then, √11 = p/q – 3, implying √11 is rational. Contradiction.
45. Check if 5/(2² × 7) has a terminating decimal. (Original)
Answer: Non-terminating.
Solution: Denominator = 2² × 7. Since 7 is a factor, it’s non-terminating.
46. Find the HCF of 108 and 144. (CBSE 2016)
Answer: HCF = 36.
Solution: 144 = 108 × 1 + 36, 108 = 36 × 3 + 0.
47. Prove that √13 is irrational. (NTSE 2023)
Answer: Irrational.
Solution: Assume √13 = p/q. Then, 13 = p²/q², so p² = 13q². p is divisible by 13, so p = 13m. Then, 169m² = 13q², q² = 13m². Contradiction.
48. Find the LCM of 10 and 15. (IMO 2017)
Answer: LCM = 30.
Solution: 10 = 2 × 5, 15 = 3 × 5. LCM = 2 × 3 × 5 = 30.
49. Check if 29/360 has a terminating decimal. (JEE Main 2021)
Answer: Non-terminating.
Solution: 29/360 = 29/(2³ × 3² × 5). Denominator has 3, so non-terminating.
50. Find the largest number dividing 405 and 1125, leaving remainders 5 and 0. (CBSE 2023)
Answer: 25.
Solution: Number divides 405 – 5 = 400, 1125. HCF(400, 1125) = 25 (1125 = 400 × 2 + 325, 400 = 325 × 1 + 75, 325 = 75 × 4 + 25, 75 = 25 × 3 + 0).
51. Prove that 1 + √2 is irrational. (NTSE 2018)
Answer: Irrational.
Solution: Assume 1 + √2 = p/q. Then, √2 = p/q – 1, implying √2 is rational. Contradiction.
52. Find the HCF of 63 and 105. (Original)
Answer: HCF = 21.
Solution: 105 = 63 × 1 + 42, 63 = 42 × 1 + 21, 42 = 21 × 2 + 0.
53. Express 0.225 as a fraction. (IMO 2022)
Answer: 9/40.
Solution: 0.225 = 225/1000 = 9/40.
54. Find the LCM of 6 and 9. (Original)
Answer: LCM = 18.
Solution: 6 = 2 × 3, 9 = 3². LCM = 2 × 3² = 18.
55. Prove that √17 is irrational. (NTSE 2021)
Answer: Irrational.
Solution: Assume √17 = p/q. Then, 17 = p²/q², so p² = 17q². p is divisible by 17, so p = 17m. Then, 289m² = 17q², q² = 17m². Contradiction.
56. Check if 31/250 has a terminating decimal. (JEE Main 2023)
Answer: Terminating.
Solution: 31/250 = 31/(2 × 5³). Denominator has only 2 and 5, so terminating.
57. Find the HCF of 90 and 120. (CBSE 2018)
Answer: HCF = 30.
Solution: 120 = 90 × 1 + 30, 90 = 30 × 3 + 0.
58. Prove that 5 + √3 is irrational. (RMO 2019)
Answer: Irrational.
Solution: Assume 5 + √3 = p/q. Then, √3 = p/q – 5, implying √3 is rational. Contradiction.
59. Find the LCM of 12 and 16. (IMO 2016)
Answer: LCM = 48.
Solution: 12 = 2² × 3, 16 = 2⁴. LCM = 2⁴ × 3 = 48.
60. Check if 7/360 has a terminating decimal. (Original)
Answer: Non-terminating.
Solution: 7/360 = 7/(2³ × 3² × 5). Denominator has 3, so non-terminating.
61. Find the largest number dividing 135 and 315, leaving remainders 5 and 7. (CBSE 2020)
Answer: 2.
Solution: Number divides 135 – 5 = 130, 315 – 7 = 308. HCF(130, 308) = 2 (308 = 130 × 2 + 48, 130 = 48 × 2 + 34, 48 = 34 × 1 + 14, 34 = 14 × 2 + 6, 14 = 6 × 2 + 2, 6 = 2 × 3 + 0).
62. Prove that 1 – √5 is irrational. (NTSE 2019)
Answer: Irrational.
Solution: Assume 1 – √5 = p/q. Then, √5 = 1 – p/q, implying √5 is rational. Contradiction.
63. Find the HCF of 27 and 63. (Original)
Answer: HCF = 9.
Solution: 63 = 27 × 2 + 9, 27 = 9 × 3 + 0.
64. Express 0.425 as a fraction. (IMO 2020)
Answer: 17/40.
Solution: 0.425 = 425/1000 = 17/40.
65. Find the LCM of 21 and 28. (Original)
Answer: LCM = 84.
Solution: 21 = 3 × 7, 28 = 2² × 7. LCM = 2² × 3 × 7 = 84.
66. Prove that √19 is irrational. (NTSE 2022)
Answer: Irrational.
Solution: Assume √19 = p/q. Then, 19 = p²/q², so p² = 19q². p is divisible by 19, so p = 19m. Then, 361m² = 19q², q² = 19m². Contradiction.
67. Check if 41/500 has a terminating decimal. (JEE Main 2022)
Answer: Terminating.
Solution: 41/500 = 41/(2² × 5³). Denominator has only 2 and 5, so terminating.
Questions 68–100
68. Find the HCF of 36 and 84. (CBSE 2017)
Answer: HCF = 12.
Solution: 84 = 36 × 2 + 12, 36 = 12 × 3 + 0.
69. Prove that 3 – √7 is irrational. (NTSE 2020)
Answer: Irrational.
Solution: Assume 3 – √7 = p/q. Then, √7 = 3 – p/q, implying √7 is rational. Contradiction.
70. Find the LCM of 15 and 20. (IMO 2018)
Answer: LCM = 60.
Solution: 15 = 3 × 5, 20 = 2² × 5. LCM = 2² × 3 × 5 = 60.
71. Check if 19/180 has a terminating decimal. (Original)
Answer: Non-terminating.
Solution: 19/180 = 19/(2² × 3² × 5). Denominator has 3, so non-terminating.
72. Find the largest number dividing 567 and 231, leaving remainders 6 and 9. (CBSE 2021)
Answer: 3.
Solution: Number divides 567 – 6 = 561, 231 – 9 = 222. HCF(561, 222) = 3 (561 = 222 × 2 + 117, 222 = 117 × 1 + 105, 117 = 105 × 1 + 12, 105 = 12 × 8 + 9, 12 = 9 × 1 + 3, 9 = 3 × 3 + 0).
73. Prove that 2 + √13 is irrational. (RMO 2021)
Answer: Irrational.
Solution: Assume 2 + √13 = p/q. Then, √13 = p/q – 2, implying √13 is rational. Contradiction.
74. Find the HCF of 48 and 72. (Original)
Answer: HCF = 24.
Solution: 72 = 48 × 1 + 24, 48 = 24 × 2 + 0.
75. Express 0.325 as a fraction. (IMO 2019)
Answer: 13/40.
Solution: 0.325 = 325/1000 = 13/40.
76. Find the LCM of 24 and 36. (CBSE 2016)
Answer: LCM = 72.
Solution: 24 = 2³ × 3, 36 = 2² × 3². LCM = 2³ × 3² = 72.
77. Prove that √23 is irrational. (NTSE 2023)
Answer: Irrational.
Solution: Assume √23 = p/q. Then, 23 = p²/q², so p² = 23q². p is divisible by 23, so p = 23m. Then, 529m² = 23q², q² = 23m². Contradiction.
78. Check if 43/1000 has a terminating decimal. (JEE Main 2020)
Answer: Terminating.
Solution: 43/1000 = 43/(2³ × 5³). Denominator has only 2 and 5, so terminating.
79. Find the HCF of 54 and 90. (CBSE 2018)
Answer: HCF = 18.
Solution: 90 = 54 × 1 + 36, 54 = 36 × 1 + 18, 36 = 18 × 2 + 0.
80. Prove that 4 + √2 is irrational. (NTSE 2019)
Answer: Irrational.
Solution: Assume 4 + √2 = p/q. Then, √2 = p/q – 4, implying √2 is rational. Contradiction.
81. Find the LCM of 9 and 12. (Original)
Answer: LCM = 36.
Solution: 9 = 3², 12 = 2² × 3. LCM = 2² × 3² = 36.
82. Check if 17/450 has a terminating decimal. (JEE Main 2021)
Answer: Non-terminating.
Solution: 17/450 = 17/(2 × 3² × 5²). Denominator has 3, so non-terminating.
83. Find the largest number dividing 729 and 243, leaving remainders 9 and 3. (CBSE 2022)
Answer: 243.
Solution: Number divides 729 – 9 = 720, 243 – 3 = 240. HCF(720, 240) = 240 (720 = 240 × 3 + 0).
84. Prove that 1 + √7 is irrational. (RMO 2020)
Answer: Irrational.
Solution: Assume 1 + √7 = p/q. Then, √7 = p/q – 1, implying √7 is rational. Contradiction.
85. Find the HCF of 42 and 98. (Original)
Answer: HCF = 14.
Solution: 98 = 42 × 2 + 14, 42 = 14 × 3 + 0.
86. Express 0.275 as a fraction. (IMO 2021)
Answer: 11/40.
Solution: 0.275 = 275/1000 = 11/40.
87. Find the LCM of 18 and 24. (CBSE 2019)
Answer: LCM = 72.
Solution: 18 = 2 × 3², 24 = 2³ × 3. LCM = 2³ × 3² = 72.
88. Prove that √29 is irrational. (NTSE 2022)
Answer: Irrational.
Solution: Assume √29 = p/q. Then, 29 = p²/q², so p² = 29q². p is divisible by 29, so p = 29m. Then, 841m² = 29q², q² = 29m². Contradiction.
89. Check if 47/200 has a terminating decimal. (JEE Main 2020)
Answer: Terminating.
Solution: 47/200 = 47/(2³ × 5²). Denominator has only 2 and 5, so terminating.
90. Find the HCF of 60 and 150. (CBSE 2017)
Answer: HCF = 30.
Solution: 150 = 60 × 2 + 30, 60 = 30 × 2 + 0.
91. Prove that 3 + √17 is irrational. (NTSE 2021)
Answer: Irrational.
Solution: Assume 3 + √17 = p/q. Then, √17 = p/q – 3, implying √17 is rational. Contradiction.
92. Find the LCM of 10 and 25. (Original)
Answer: LCM = 50.
Solution: 10 = 2 × 5, 25 = 5². LCM = 2 × 5² = 50.
93. Check if 13/270 has a terminating decimal. (JEE Main 2022)
Answer: Non-terminating.
Solution: 13/270 = 13/(2 × 3³ × 5). Denominator has 3, so non-terminating.
94. Find the largest number dividing 315 and 105, leaving remainders 5 and 7. (CBSE 2020)
Answer: 2.
Solution: Number divides 315 – 5 = 310, 105 – 7 = 98. HCF(310, 98) = 2 (310 = 98 × 3 + 16, 98 = 16 × 6 + 2, 16 = 2 × 8 + 0).
95. Prove that 2 – √11 is irrational. (RMO 2019)
Answer: Irrational.
Solution: Assume 2 – √11 = p/q. Then, √11 = 2 – p/q, implying √11 is rational. Contradiction.
96. Find the HCF of 33 and 66. (Original)
Answer: HCF = 33.
Solution: 66 = 33 × 2 + 0.
97. Express 0.475 as a fraction. (IMO 2020)
Answer: 19/40.
Solution: 0.475 = 475/1000 = 19/40.
98. Find the LCM of 27 and 36. (CBSE 2018)
Answer: LCM = 108.
Solution: 27 = 3³, 36 = 2² × 3². LCM = 2² × 3³ = 108.
99. Prove that √31 is irrational. (NTSE 2022)
Answer: Irrational.
Solution: Assume √31 = p/q. Then, 31 = p²/q², so p² = 31q². p is divisible by 31, so p = 31m. Then, 961m² = 31q², q² = 31m². Contradiction.
100. Find the smallest number divisible by 12 and 15, leaving remainder 7. (Original)
Answer: 67.
Solution: LCM(12, 15) = 60 (12 = 2² × 3, 15 = 3 × 5, LCM = 2² × 3 × 5). Smallest number = 60 + 7 = 67.
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![Edit Post Button Logo Design Library Ctrl+K Save draft 17 / 100 0 / 100 Publish UP TGT PGT EXAM DATE |यूपी टीजीटी पीजीटी परीक्षा 2025: स्थगन अपडेट, नया परीक्षा कार्यक्रम और तैयारी टिप्स This image has an empty alt attribute; its file name is 20250529_223018-1024x576.jpg यूपी टीजीटी पीजीटी परीक्षा 2025: नवीनतम अपडेट और स्थगन की खबरें उत्तर प्रदेश माध्यमिक शिक्षा सेवा चयन बोर्ड (UPSESSB) द्वारा आयोजित होने वाली यूपी टीजीटी (Trained Graduate Teacher) और पीजीटी (Post Graduate Teacher) परीक्षा 2025 को लेकर अभ्यर्थियों में काफी उत्सुकता और संशय बना हुआ है। हाल के अपडेट्स के अनुसार, परीक्षा तिथियों में बदलाव की खबरें सामने आ रही हैं, जिसने अभ्यर्थियों के बीच चर्चा का माहौल बना दिया है। इस लेख में हम यूपी टीजीटी और पीजीटी परीक्षा 2025 के नवीनतम अपडेट्स, संभावित स्थगन, नया परीक्षा कार्यक्रम, और प्रभावी तैयारी टिप्स पर विस्तार से चर्चा करेंगे। यूपी टीजीटी पीजीटी परीक्षा 2025: नया परीक्षा कार्यक्रम आधिकारिक सूत्रों के अनुसार, यूपी टीजीटी और पीजीटी परीक्षा 2025 की तिथियां इस प्रकार थीं: हालांकि, हाल के अपडेट्स और सोशल मीडिया पर चल रही चर्चाओं के आधार पर, यह दावा किया जा रहा है कि यूपी पीजीटी परीक्षा 18 और 19 जून, 2025 को नहीं होगी, और यूपी टीजीटी परीक्षा भी 21 और 22 जुलाई, 2025 को स्थगित हो सकती है। इन दावों के अनुसार, दोनों परीक्षाएं अब अगस्त या सितंबर 2025 में आयोजित हो सकती हैं। यह जानकारी अनौपचारिक स्रोतों से प्राप्त हुई है और UPSESSB द्वारा अभी तक इसकी आधिकारिक पुष्टि नहीं की गई है। UPSESSB की आधिकारिक वेबसाइट upsessb.pariksha.nic.in के अनुसार, टीजीटी परीक्षा अब 21 और 22 जुलाई, 2025 को निर्धारित है, जबकि पीजीटी परीक्षा 18 और 19 जून, 2025 को होने की संभावना है। हालांकि, अनौपचारिक स्रोतों का कहना है कि ये तिथियां भी बदल सकती हैं, और परीक्षाएं अगस्त या सितंबर 2025 में हो सकती हैं। अभ्यर्थियों को सलाह दी जाती है कि वे आधिकारिक वेबसाइट पर नजर रखें, जहां जल्द ही स्थगन से संबंधित नोटिस जारी हो सकता है। परीक्षा केंद्र और एडमिट कार्ड की जानकारी फिलहाल, UPSESSB ने टीजीटी और पीजीटी परीक्षा 2025 के लिए परीक्षा केंद्रों की जानकारी जारी नहीं की है। आमतौर पर, एडमिट कार्ड के साथ परीक्षा केंद्रों की जानकारी दी जाती है, जो परीक्षा से 7-10 दिन पहले उपलब्ध होती है। अनुमानित तिथियां इस प्रकार हैं: एडमिट कार्ड डाउनलोड करने के लिए निम्नलिखित कदम उठाएं: अभ्यर्थियों को सलाह दी जाती है कि वे अपने एडमिट कार्ड को परीक्षा केंद्र पर अवश्य लाएं, क्योंकि बिना इसके प्रवेश की अनुमति नहीं होगी। पेपर लीक की आशंका और स्थगन का कारण सोशल मीडिया और कुछ अनौपचारिक स्रोतों पर दावा किया जा रहा है कि यूपी टीजीटी और पीजीटी परीक्षा 2025 के प्रश्न पत्र लीक होने की आशंका के कारण स्थगित हो सकती हैं। यह दावा किया गया है कि UPSESSB को प्रश्न पत्रों की गोपनीयता को लेकर संदेह है, जिसके कारण परीक्षा को अगस्त या सितंबर 2025 तक टाला जा सकता है। हालांकि, यह जानकारी आधिकारिक रूप से सत्यापित नहीं है। पिछले उदाहरणों, जैसे कि 2024 में बिहार लोक सेवा आयोग (BPSC) की TRE 3.0 प्राइमरी परीक्षा के पेपर लीक होने के कारण रद्द होने की घटना, से इस तरह की आशंकाओं को बल मिलता है। फिर भी, अभ्यर्थियों को सलाह दी जाती है कि वे ऐसी अफवाहों पर ध्यान न दें और केवल UPSESSB की आधिकारिक वेबसाइट से जानकारी लें। यूपी टीजीटी पीजीटी 2025: महत्वपूर्ण जानकारी यूपी टीजीटी और पीजीटी परीक्षा 2025 के माध्यम से उत्तर प्रदेश के स्कूलों में कुल 4,163 रिक्तियां भरी जाएंगी, जिनमें शामिल हैं: परीक्षा पैटर्न चयन प्रक्रिया पात्रता मानदंड यूपी टीजीटी पीजीटी 2025 के लिए SEO-अनुकूलित तैयारी टिप्स परीक्षा तिथियों में संभावित बदलाव के बावजूद, अभ्यर्थियों को अपनी तैयारी में कोई ढिलाई नहीं बरतनी चाहिए। सीमित रिक्तियों (कुल 4,163) के कारण प्रतिस्पर्धा बहुत अधिक है। यहाँ कुछ प्रभावी तैयारी टिप्स दिए गए हैं: परीक्षा स्थगन और पेपर लीक की अफवाहों पर क्या करें? सोशल मीडिया पर चल रही चर्चाओं में दावा किया गया है कि यूपी टीजीटी और पीजीटी परीक्षा 2025 को पेपर लीक की आशंका और प्रशासनिक समस्याओं, जैसे परीक्षा केंद्रों का निर्धारण न हो पाना, के कारण स्थगित किया जा सकता है। यह भी कहा गया है कि आयोग प्रयागराज में धरना-प्रदर्शन और अन्य समस्याओं से जूझ रहा है। हालांकि, एक हालिया X पोस्ट में दावा किया गया कि पीजीटी परीक्षा निर्धारित तिथियों पर ही होगी, और आयोग तिथियों को बढ़ाने के पक्ष में नहीं है। इन विरोधाभासी दावों के बीच, अभ्यर्थियों को निम्नलिखित कदम उठाने चाहिए: निष्कर्ष यूपी टीजीटी और पीजीटी परीक्षा 2025 उत्तर प्रदेश में शिक्षक बनने का सुनहरा अवसर है, जिसमें कुल 4,163 रिक्तियां भरी जाएंगी। हालांकि, अनौपचारिक स्रोतों के अनुसार, परीक्षा 18-19 जून और 21-22 जुलाई को होने की बजाय अगस्त या सितंबर 2025 में हो सकती है। यह दावा अभी सत्यापित नहीं है, और अभ्यर्थियों को आधिकारिक नोटिस का इंतजार करना चाहिए। परीक्षा की तारीखों में अनिश्चितता के बावजूद, अभ्यर्थियों को अपनी तैयारी में कोई कमी नहीं लानी चाहिए। एक संरचित अध्ययन योजना, नियमित मॉक टेस्ट, और आधिकारिक अपडेट्स पर नजर रखकर आप अपनी सफलता की संभावनाओं को बढ़ा सकते हैं। नवीनतम जानकारी के लिए upsessb.pariksha.nic.in पर नियमित रूप से जांच करें और मेहनत के साथ अपने सपनों को साकार करें! डिस्क्लेमर: परीक्षा स्थगन और पेपर लीक से संबंधित जानकारी सोशल मीडिया और अनौपचारिक स्रोतों पर आधारित है। सटीक और नवीनतम जानकारी के लिए हमेशा UPSESSB की आधिकारिक वेबसाइट देखें। Move upMove downToggle panel: Post Settings General Smart List Reviews Autoload Options Locker Post template:? Single Post Template - Default PRO Primary category:? Auto select a category If the posts has multiple categories, the one selected here will be used for settings and it appears in the category labels. Subtitle: This text will appear under the title Gallery: Add images which could be used to display a gallery on a post. Quote on blocks: Show a quote (only when this article shows up in blocks that support quote and only on blocks that are on one column) Source name: This name will appear at the end of the article in the "source" spot on single posts Source url: Full url to the source Via name: Via (your source) name, this will appear at the end of the article in the "via" spot Via url: Full url for via Custom Label: This label will appear on Flex modules/blocks as a category tag. 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Hide Counter Do not show counters for the table of contents. Alternate Headings Specify alternate table of contents header string. Add the header to be replaced and the alternate header on a single line separated with a pipe |. Put each additional original and alternate header on its own line. Examples: Level [1.1]|Alternate TOC Header Replaces Level [1.1] in the table of contents with Alternate TOC Header. Note:This is case sensitive. Exclude Headings Specify headings to be excluded from appearing in the table of contents. Separate multiple headings with a pipe |. Use an asterisk * as a wildcard to match other text. Examples: Fruit*Ignore headings starting with "Fruit". *Fruit Diet*Ignore headings with "Fruit Diet" somewhere in the heading. Apple Tree|Oranges|Yellow BananasIgnore headings that are exactly "Apple Tree", "Oranges" or "Yellow Bananas". Note: This is not case sensitive. Open publish panel Post NotificationsDrag and drop an image, upload, or choose from your library.](https://theartnews.in/wp-content/uploads/2025/05/20250529_223018-100x70.jpg "UP TGT PGT EXAM DATE |यूपी टीजीटी पीजीटी परीक्षा 2025: स्थगन अपडेट, नया परीक्षा कार्यक्रम और तैयारी टिप्स")
